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GATE ME 2021 Official Paper: Shift 2

CT 1: Ratio and Proportion

2672

10 Questions
16 Marks
30 Mins

**Concept:**

Let total mass = m, mass of liquid mf, mass of vapour m_{g }

∴ m = m_{f} + m_{g}

Net volume = volume of liquid + volume of vapour

**V = vf × mf + vg × mg**

**Calculation:**

**Given:**

mf = 0.2m, mg = 0.8m, vf = 0.001084 m3/kg, v_{g} = 0.46242 m3/kg, V = 50 m3

V = vf × mf + v_{g} × m_{g}

50 = 0.001084 × 0.2m + 0.46242 × 0.8m

m = 135.08 kg

∴ mass of liquid vapour mixture in the tank is 135.08 kg.